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\title[Beamer Blackboard Theme]{Simple Proof}
\author{Luis R. Guzman, Jr.}
\date[\today]{{\footnotesize \today}}
\institute{{\footnotesize University of West Florida}}
\begin{document}
\ECFAugie
\begin{frame}[t]
\maketitle
\end{frame}
\begin{frame}[t]
\frametitle{\Large Outline of Talk}
\begin{itemize}
\item Point one
\item Point two
\item ...
\end{itemize}
\end{frame}
\begin{frame}[t]
{1 = 0.999...}
Proof.
Set $x = 0.999\ldots$. Then
\begin{table}
\centering
\begin{tabular}{r r@{.} l}
& $10x$ $=$ $9$&$999\ldots$\\
$-$& $x$ $=$ $0$&$999\ldots$\\\hline
& $9x$ $=$ $9$&$000\ldots$
\end{tabular}
\end{table}
Thus $x = 1.000\dots$ $\Box$
\end{frame}
\end{document}