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Projet Euler

Voici quelques problèmes tirés du Projet Euler: https://projecteuler.net. Calculez les réponses aux questions et vérifiez sur le site que vous avez trouvé la solution. Vous pouvez rajouter d'autres problèmes après ceux proposés. A vous d'écrire vos propres programmes ou de chercher dans Sage les fonctionalités dont vous avez besoin.

Problème 1

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

Problème 2

Each new term in the Fibonacci sequence is generated by adding the previous two terms. By starting with 1 and 2, the first 10 terms will be:

1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ...

By considering the terms in the Fibonacci sequence whose values do not exceed four million, find the sum of the even-valued terms.

Problème 3

The prime factors of 13195 are 5, 7, 13 and 29.

What is the largest prime factor of the number 600851475143 ?

Problème 4

A palindromic number reads the same both ways. The largest palindrome made from the product of two 2-digit numbers is 9009 = 91 × 99.

Find the largest palindrome made from the product of two 3-digit numbers.

Problème 5

2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder.

What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20?

Problème 6

The sum of the squares of the first ten natural numbers is, 12+22+...+102=3851^2 + 2^2 + ... + 10^2 = 385

The square of the sum of the first ten natural numbers is, (1+2+...+10)2=552=3025(1 + 2 + ... + 10)^2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025385=26403025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

Problème 7

By listing the first six prime numbers: 2, 3, 5, 7, 11, and 13, we can see that the 6th prime is 13.

What is the 10 001st prime number?

Problème 8

The four adjacent digits in this 1000-digit number that have the greatest product are 9 × 9 × 8 × 9 = 5832. Find the thirteen adjacent digits in this 1000-digit number that have the greatest product. What is the value of this product?

A = 7316717653133062491922511967442657474235534919493496983520312774506326239578318016984801869478851843858615607891129494954595017379583319528532088055111254069874715852386305071569329096329522744304355766896648950445244523161731856403098711121722383113622298934233803081353362766142828064444866452387493035890729629049156044077239071381051585930796086670172427121883998797908792274921901699720888093776657273330010533678812202354218097512545405947522435258490771167055601360483958644670632441572215539753697817977846174064955149290862569321978468622482839722413756570560574902614079729686524145351004748216637048440319989000889524345065854122758866688116427171479924442928230863465674813919123162824586178664583591245665294765456828489128831426076900422421902267105562632111110937054421750694165896040807198403850962455444362981230987879927244284909188845801561660979191338754992005240636899125607176060588611646710940507754100225698315520005593572972571636269561882670428252483600823257530420752963450

Problème 9

A Pythagorean triplet is a set of three natural numbers, a<b<ca < b < c, for which, a2+b2=c2a^2 + b^2 = c^2

For example, 32+42=9+16=25=523^2 + 4^2 = 9 + 16 = 25 = 5^2.

There exists exactly one Pythagorean triplet for which a+b+c=1000a + b + c = 1000. Find the product abc.

Problème 10

The sum of the primes below 10 is 2+3+5+7=172 + 3 + 5 + 7 = 17.

Find the sum of all the primes below two million.

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