Contact
CoCalc Logo Icon
StoreFeaturesDocsShareSupport News AboutSign UpSign In
| Download
Views: 123
Kernel: Python 2

ATMS 391: Homework 10


Problem 1

Perform a random sampling exercise on the Chicago August temperature dataset to determine the 90% confidence interval of the mean temperature for the month when randomly subsetting the data for 10, 50, 100, and 500 samples.

Plot your results using an errorbar plot: [http://matplotlib.org/1.2.1/examples/pylab_examples/errorbar_demo.html]

from __future__ import print_function, division %matplotlib inline import numpy as np import scipy.stats import pandas as pd import matplotlib.pyplot as plt import random from ipywidgets import interact, interactive, fixed import ipywidgets as widgets df = pd.read_csv('chicago_hourly_aug_2015.csv', header=6) temp = df['DryBulbCelsius'].values def make_sample(n=100): sample = np.random.choice(temp,n) return sample def sample_stat(sample): return sample.mean() def compute_sample_statistics(n=100, iters=1000): stats = [sample_stat(make_sample(n)) for i in range(iters)] #print sample_stat(make_sample(n)) return np.array(stats) sample_10 = compute_sample_statistics(10) mean_10 = np.mean(sample_10) conf_int_10 = np.percentile(sample_10, [5, 95]) sample_50 = compute_sample_statistics(50) mean_50 = np.mean(sample_50) conf_int_50 = np.percentile(sample_50, [5, 95]) sample_100 = compute_sample_statistics(100) mean_100 = np.mean(sample_100) conf_int_100 = np.percentile(sample_100, [5, 95]) sample_500 = compute_sample_statistics(500) mean_500 = np.mean(sample_500) conf_int_500 = np.percentile(sample_500, [5, 95]) x = [10, 50, 100, 500] y = [mean_10, mean_50, mean_100, mean_500] y_err_lower = [mean_10-conf_int_10[0], mean_50-conf_int_50[0], mean_100-conf_int_100[0], mean_500-conf_int_500[0]] y_err_higher = [conf_int_10[1]-mean_10, conf_int_50[1]-mean_50, conf_int_100[1]-mean_100, conf_int_500[1]-mean_500] plt.figure() plt.plot(x,y) plt.errorbar(x, y, yerr=[y_err_lower, y_err_higher], fmt='o') plt.xlim(0,510) plt.xlabel('Number of samples') plt.ylabel('Mean temperature') plt.show()
Image in a Jupyter notebook

Problem 2

Using the global precipitation data file (prec.mon.mean.nc), for January and July, fit a Gamma distribution to the monthly precipitation accumulations for the record of the data. Plot maps for January and July separately of the:

  • mean precipitation

  • standard deviation of precipitation

  • Gamma alpha parameter

  • Gamma beta parameter

  • Using a chi-squared test, and separating the data into 10 equally-spaced bins covering the range of values at each point, indicate on a map the locations where the fit is statistically significant at the 90% level. (i.e., see if you can or cannot reject the null hypothesis that the data follow a Gamma distribution as fitted).

Read this as it will illustrate the procedure. [http://www.stat.yale.edu/Courses/1997-98/101/chigf.htm]

import netCDF4 as nc from datetime import datetime import xray from mpl_toolkits.basemap import Basemap data = xray.open_dataset('precip.mon.total.nc') precip = data['precip'] dates = pd.DatetimeIndex(data['time'].values) precip_jan = precip[dates.month==1] #precip_jan['time'] precip_jul = precip[dates.month==7] #precip_jul['time'] # calculate mean and std mean_jan = np.mean(precip_jan, axis=0) std_jan = np.std(precip_jan, axis=0) mean_jul = np.mean(precip_jul, axis=0) std_jul = np.std(precip_jul, axis=0) # plot lat_1d = mean_jan['lat'] lon_1d = mean_jan['lon'] lat_1d = lat_1d[:].squeeze() lon_1d = lon_1d[:].squeeze() lon_2d, lat_2d = np.meshgrid(lon_1d, lat_1d) fig=plt.figure(figsize=(11,8.5)) #width, height in inches map = Basemap(lon_0=180, resolution='l', projection='cyl') CS=map.contourf(lon_2d, lat_2d, mean_jan) plt.clabel(CS,inline=1, fontsize=14, fmt='%1.0f') map.drawcoastlines() map.drawstates() map.drawcountries(linewidth=1.5) plt.title('Mean precipitation for January', fontsize=20) plt.colorbar(fraction=0.025, pad=0.04) plt.show()
Image in a Jupyter notebook
fig=plt.figure(figsize=(11,8.5)) #width, height in inches map = Basemap(lon_0=180, resolution='l', projection='cyl') CS=map.contourf(lon_2d, lat_2d, std_jan) plt.clabel(CS,inline=1, fontsize=14, fmt='%1.0f') map.drawcoastlines() map.drawstates() map.drawcountries(linewidth=1.5) plt.title('Std precipitation for January', fontsize=20) plt.colorbar(fraction=0.025, pad=0.04) plt.show()
Image in a Jupyter notebook
alpha_jan = mean_jan * mean_jan / std_jan beta_jan = std_jan / mean_jan
fig=plt.figure(figsize=(11,8.5)) #width, height in inches map = Basemap(lon_0=180, resolution='l', projection='cyl') CS=map.contourf(lon_2d, lat_2d, alpha_jan) plt.clabel(CS,inline=1, fontsize=14, fmt='%1.0f') map.drawcoastlines() map.drawstates() map.drawcountries(linewidth=1.5) plt.title('alpha for January', fontsize=20) plt.colorbar(fraction=0.025, pad=0.04) plt.show()
Image in a Jupyter notebook
fig=plt.figure(figsize=(11,8.5)) #width, height in inches map = Basemap(lon_0=180, resolution='l', projection='cyl') CS=map.contourf(lon_2d, lat_2d, beta_jan) plt.clabel(CS,inline=1, fontsize=14, fmt='%1.0f') map.drawcoastlines() map.drawstates() map.drawcountries(linewidth=1.5) plt.title('beta for January', fontsize=20) plt.colorbar(fraction=0.025, pad=0.04) plt.show()
Image in a Jupyter notebook
#precip_jan import math significance=np.zeros((36,72)) for i in range(36): for j in range (72): temp = precip_jan[:,i,j] hist, edge = np.histogram(temp, bins=10) chisq, p = scipy.stats.chisquare(hist); if (math.isnan(p)): significance[i,j]=1 else: significance[i,j]=p fig=plt.figure(figsize=(11,8.5)) #width, height in inches map = Basemap(lon_0=180, resolution='l', projection='cyl') CS=map.contourf(lon_2d, lat_2d, significance) plt.clabel(CS,inline=1, fontsize=14, fmt='%1.0f') map.drawcoastlines() map.drawstates() map.drawcountries(linewidth=1.5) plt.title('significance for January', fontsize=20) plt.colorbar(fraction=0.025, pad=0.04) plt.show()
Image in a Jupyter notebook