CoCalc Public Filessupport / 2014-12-08 continuous compounding.sagewsOpen in with one click!
Authors: Harald Schilly, ℏal Snyder, William A. Stein
Description: Jupyter notebook support/2015-06-04-141749-bokeh.ipynb
%var w show(solve(2*w^(-4/3) == 1/4, w))
[w=i834,w=i834,w=834,w13=814]\left[w = -i \cdot 8^{\frac{3}{4}}, w = i \cdot 8^{\frac{3}{4}}, w = 8^{\frac{3}{4}}, w^{\frac{1}{3}} = -8^{\frac{1}{4}}\right]
65528518-7ba1-43df-a8a4-99a683fed083 a = 4^(1/4); a
4^(1/4)
a.full_simplify()
sqrt(2)
show(a.full_simplify())
2\sqrt{2}
v = [] for m in [1,10,..,1000]: t = (1+0.09/m)^(m) v.append((m,t))
f(x) = e^(0.09) line(v) + plot(f,(0,m), color='red')