CoCalc Public FilesWeek 6 / Lab 6 - ANOVA-corrected.ipynbOpen with one click!
Author: Dean Neutel
Views : 714
Compute Environment: Ubuntu 18.04 (Deprecated)

Lab 6: Comparing Three or More Groups with ANOVA

Often, we have to compare data from three or more groups to see if one or more of them is different from the others. To do this, scientists use a statistic called the F- statistic, defined as the ratio of the among-group variances to the within-group variance. The between-group variance is the sum of the squared differences between the group means and the mean of all the samples taken together, called the grand mean. The within-group variance is the sum of the individual group variances. In LS 40, we will use a variation of the F-statistic that does not require squaring, called the F-like statistic.

  1. Import pandas, Numpy and Seaborn.
In [2]:
#1 import pandas as pd import numpy as np import seaborn as sns

In this lab, we will examine the results of a hypothetical study comparing the effectiveness of different pain relief medications on migraine headaches. For the experiment, 27 volunteers with migraines were selected and 9 were randomly assigned to one of three drug formulations. The subjects were instructed to take the drug during their next migraine headache episode and to report their pain on a scale of 1 = no pain to 10 =extreme pain 30 minutes after taking the drug.

  1. Using the pandas read_csv function, import the file migraines.csv and show the data.
In [3]:
#2 migraines = pd.read_csv("migraines.csv") migraines
Drug A Drug B Drug C
0 4 7 6
1 5 8 7
2 4 4 6
3 2 5 6
4 2 4 7
5 4 6 5
6 3 5 6
7 3 8 5
8 3 7 5
  1. Visualize the data. Use as many different plots as you need to get a sense of the distributions. What are your initial impressions?
In [4]:
#3 p=sns.swarmplot(data=migraines) p.set(xlabel="Drug Group",ylabel="Count");
In [5]:
drug_a = list(migraines["Drug A"]) drug_b = list(migraines["Drug B"]) drug_c = list(migraines["Drug C"]) p=sns.distplot(drug_a, kde=True, bins=4) p=sns.distplot(drug_b, kde=True, color="green", bins=4) p=sns.distplot(drug_c, kde=True, color="orange", bins=4) p.set(xlabel="Drug Group", ylabel="Count");

Computing the F-like statistic

In the next several exercises, you will compute the F-like statistic for your data.

Flike=naa~G~+nbb~G~+ncc~G~Σaia~+Σbib~+Σcic~F-like= \frac{n_{a}|\widetilde{a}-\widetilde{G}|+n_{b}|\widetilde{b}-\widetilde{G}|+n_{c}|\widetilde{c}-\widetilde{G}|}{\Sigma|a_{i}-\widetilde{a}|+\Sigma|b_{i}-\widetilde{b}|+\Sigma|c_{i}-\widetilde{c}|}

Here, nxn_x is the size of group xx and symbols with ~s over them represent medians, with G~\widetilde{G} being the grand median -- the median of all the data taken together.

Each quantity you compute in this section should be assigned to a variable.

  1. Find the median of each column. HINT: pandas data frames have a built-in function for columnwise medians, so you can just use df.median(), where df is the name of your data frame.
In [6]:
#4 medians = migraines.median() medians
Drug A 3.0 Drug B 6.0 Drug C 6.0 dtype: float64
  1. Find the grand median (the median of the whole sample). HINT: Use np.median.
In [7]:
#5 grand_median = np.median(migraines) grand_median
5.0
  1. Find the numerator of the F-like statistic (variation among groups). HINT: When working with data frames and NumPy arrays, you can do computations like addition and multiplication directly, without for loops (unlike in regular Python). Also, Numpy has abs and sum functions.
In [8]:
#6 n = len(migraines) variation_between_groups = (n*abs(medians["Drug A"]-grand_median))+(n*abs(medians["Drug B"]-grand_median))+(n*abs(medians["Drug C"]-grand_median)) variation_between_groups
36.0
  1. Compute the denominator of the F-like statistic. This represents variation within groups. HINT: Numpy and pandas will handle columns automatically.
In [9]:
#7 variation_within_groups = sum(np.sum(abs(migraines-medians))) variation_within_groups
24.0
  1. Compute F-like statistic, which is the ratio variation among groupsvariation within groups\frac{\text{variation among groups}}{\text{variation within groups}}.
In [10]:
#8 F_observed = (variation_between_groups)/(variation_within_groups) F_observed
1.5

Bootstrapping

We now want to find a p-value for our data by simulating the null hypothesis. This, of course, means computing the F-like statistic each time, which takes a lot of code and would make a mess in the bootstrap loop. Instead, we will package our code into a function and call this function whereever necessary.

  1. Write a function that will compute the F-like statistic for this dataset or one of the same size.
In [11]:
#9 def F_like_function(data): n = len(data) variation_within_groups = sum(np.sum(abs(data-data.median()))) variation_between_groups = (n*abs(data.median()[0]-np.median(data)))+(n*abs(data.median()[1]-np.median(data)))+(n*abs(data.median()[2]-np.median(data))) F_like = (variation_between_groups)/(variation_within_groups) return(F_like) F_like_function(migraines)
1.5

We now want to simulate the null hypothesis that there is no difference between the groups. To do this, we have to make all the data into one dataset, sample pseudo-groups from it, and compute the F-like statistic for the resampled data.

  1. Use the code alldata = np.concatenate([migraine["Drug A"], migraine["Drug B"], migraine["Drug C"]]) (this assumes your data frame is called "migraine") to put all the data into one 1-D array.
In [12]:
#10 alldata = np.concatenate([migraines["Drug A"], migraines["Drug B"], migraines["Drug C"]]) alldata
array([4, 5, 4, 2, 2, 4, 3, 3, 3, 7, 8, 4, 5, 4, 6, 5, 8, 7, 6, 7, 6, 6, 7, 5, 6, 5, 5])
  1. Sample three groups of the appropriate size from alldata. Assign each to a variable.
In [13]:
#11 a_random = np.random.choice(alldata,len(migraines["Drug A"])) b_random = np.random.choice(alldata,len(migraines["Drug B"])) c_random = np.random.choice(alldata,len(migraines["Drug C"])) display("New Drug A Group", a_random,"New Drug B Group", b_random,"New Drug C Group", c_random)
'New Drug A Group'
array([7, 8, 5, 4, 3, 7, 5, 5, 7])
'New Drug B Group'
array([6, 6, 7, 4, 5, 5, 6, 4, 2])
'New Drug C Group'
array([8, 4, 6, 6, 7, 4, 7, 5, 4])
  1. Make the three samples into a data frame. To do this, use the NumPy function column_stack to put the 1-D arrays side by side and then use the pandas function DataFrame to convert the result into a data frame.
In [14]:
#12 column = np.column_stack((a_random,b_random,c_random)) random_data_frame = pd.DataFrame(column) random_data_frame
0 1 2
0 7 6 8
1 8 6 4
2 5 7 6
3 4 4 6
4 3 5 7
5 7 5 4
6 5 6 7
7 5 4 5
8 7 2 4
  1. Compute the F-like statistic for your resampled data.
In [15]:
#13 F_like_function(random_data_frame)
0.2727272727272727
  1. Do the above steps 10,000 times to simulate the null hypothesis, storing the results.
In [33]:
#14 F_like = [] alldata = np.concatenate([migraines["Drug A"], migraines["Drug B"], migraines["Drug C"]]) total = 10000 for i in range(total): a_random = np.random.choice(alldata,len(migraines["Drug A"])) b_random = np.random.choice(alldata,len(migraines["Drug B"])) c_random = np.random.choice(alldata,len(migraines["Drug C"])) column = np.column_stack((a_random,b_random,c_random)) random_data_frame = pd.DataFrame(column) new_F_like = F_like_function(random_data_frame) F_like.append(new_F_like)
WARNING: Some output was deleted.
In [ ]:
  1. Find the p-value for your data. What do you conclude about the migraine treatments? Use α\alpha=0.05 for NHST.
In [ ]:
#15 F_like = [] alldata = np.concatenate([migraines["Drug A"], migraines["Drug B"], migraines["Drug C"]]) total = 10000 for i in range(total): a_random = np.random.choice(alldata,len(migraines["Drug A"])) b_random = np.random.choice(alldata,len(migraines["Drug B"])) c_random = np.random.choice(alldata,len(migraines["Drug C"])) column = np.column_stack((a_random,b_random,c_random)) random_data_frame = pd.DataFrame(column) new_F_like = F_like_function(random_data_frame) F_like.append(new_F_like) pvalue = (sum(F_like>=F_observed))/total display("P-Value", pvalue)

Post Hoc Analysis

Having obtained a significant result from the omnibus test, we can now try to track down the source of the significance. Which groups are actually different from which?

  1. Perform pairwise two-group comparisons and record the p-value for each.
In [20]:
#16 total = 10000 differenceMedian = np.median(migraines["Drug A"]) - np.median(migraines["Drug B"]) other_limit = -differenceMedian limits = [differenceMedian,other_limit] a_b_difference = np.zeros(total) alldata = np.concatenate([migraines["Drug A"], migraines["Drug B"]]) for i in range(total): Random_Drug_A = np.random.choice(alldata, len(migraines["Drug A"])) Random_Drug_B = np.random.choice(alldata, len(migraines["Drug B"])) difference = np.median(Random_Drug_A) - np.median(Random_Drug_B) a_b_difference[i] = difference pvalueAB = (sum(a_b_difference>=max(limits))+sum(a_b_difference<=min(limits)))/total display("P-Value (A-B)", pvalueAB)
'P-Value (A-B)'
0.0437
In [29]:
total = 10000 differenceMedian = np.median(migraines["Drug C"]) - np.median(migraines["Drug B"]) other_limit = -differenceMedian limits = [differenceMedian,other_limit] c_b_difference = np.zeros(total) alldata = np.concatenate([migraines["Drug C"], migraines["Drug B"]]) for i in range(total): Random_Drug_C = np.random.choice(alldata, len(migraines["Drug C"])) Random_Drug_B = np.random.choice(alldata, len(migraines["Drug B"])) difference = np.median(Random_Drug_C) - np.median(Random_Drug_B) c_b_difference[i] = difference pvalueBC = np.sum(np.sum(c_b_difference>=max(limits))+np.sum(c_b_difference<=min(limits)))/total display("P-Value (B-C)", pvalueBC)
'P-Value (B-C)'
1.461
In [22]:
total = 10000 differenceMedian = np.median(migraines["Drug A"]) - np.median(migraines["Drug C"]) other_limit = -differenceMedian limits = [differenceMedian,other_limit] a_b_difference = np.zeros(total) alldata = np.concatenate([migraines["Drug A"], migraines["Drug C"]]) for i in range(total): Random_Drug_A = np.random.choice(alldata, len(migraines["Drug A"])) Random_Drug_B = np.random.choice(alldata, len(migraines["Drug B"])) difference = np.median(Random_Drug_A) - np.median(Random_Drug_B) a_b_difference[i] = difference pvalueAC = (sum(a_b_difference>=max(limits))+sum(a_b_difference<=min(limits)))/total display("P-Value (A-C)", pvalueAC)
'P-Value (A-C)'
0.0203
  1. Use the list of p-values from your two-group comparisons and the Benjamini-Hochberg method below to determine which two-group comparisons have a significant difference at α\alpha=0.05. See more details in "Controlling the False Positive Rate with Multiple Comparisons Corrections" PDF on Week 6 on CCLE site.

    import statsmodels.stats.multitest as smm
    smm.multipletests(pvals, alpha=critical_alpha, method='fdr_bh')
In [25]:
#17 import statsmodels.stats.multitest as smm smm.multipletests(pvalueAB, alpha=0.05, method='fdr_bh')+smm.multipletests(pvalueBC, alpha=0.05, method='fdr_bh')+smm.multipletests(pvalueAC, alpha=0.05, method='fdr_bh')
(array([ True]), array([0.0437]), 0.050000000000000044, 0.05, array([False]), array([1.]), 0.050000000000000044, 0.05, array([ True]), array([0.0203]), 0.050000000000000044, 0.05)
  1. Write a sentence or two describing your findings.
In [22]:
#18